The number of protons, neutrons present in the species Br3580

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80, 35

35,45

80,45

45,35

answer is B.

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Detailed Solution

For the given species Br3580 ,Atomic no. Z=35 , Hence no. of protons = 35.Mass no A=80 , Hence no. of neutrons=A-Z = 80-35 = 45

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