Q.
The number of protons, neutrons present in the species Br3580
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a
80, 35
b
35,45
c
80,45
d
45,35
answer is B.
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Detailed Solution
For the given species Br3580 ,Atomic no. Z=35 , Hence no. of protons = 35.Mass no A=80 , Hence no. of neutrons=A-Z = 80-35 = 45
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