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Q.

Number of revolutions made by an electron in Bohr’s 2nd orbit of hydrogen atom in one second is (approx)

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a

8.3×1014

b

6.66×1015

c

5.3×106

d

4.5×1012

answer is A.

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Detailed Solution

[Formula]: Frequency =V2πr=2.18×106×Zn2π×0.529×n2Z=2.18×1062×n3×0.529=2.18×106×12×3.14×23×0.529=8.3×1014(or)[Formula]: Orbital frequency =Z2n3×6.66×1015=18×6.66×1015=8.3×1014

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Number of revolutions made by an electron in Bohr’s 2nd orbit of hydrogen atom in one second is (approx)