The number of sodium atoms in 2 mol of sodium ferrocyanide is

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48×1023

26×1023

34×1023

12×1023

answer is A.

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Detailed Solution

As we know that four sodium atoms are present in sodium ferrocyanide Na4Fe(CN)6Hence, number of Na atoms - No. of moles x number of atom× Avogadro's number2×4×6.023×1023=48×1023

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