The number of sodium atoms in 2 mol of sodium ferrocyanide is
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a
48×1023
b
26×1023
c
34×1023
d
12×1023
answer is A.
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Detailed Solution
As we know that four sodium atoms are present in sodium ferrocyanide Na4Fe(CN)6Hence, number of Na atoms - No. of moles x number of atom× Avogadro's number2×4×6.023×1023=48×1023