Number of stereoisomers for the complex, [Pt(NH3)(Br)(Cl)(py)] are ‘X’ and for the complex, [Pt(NH3)2Cl2] are ‘Y’ . Sum of ‘X’ and ‘Y’ is
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a
5
b
4
c
6
d
3
answer is A.
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Detailed Solution
A) [Pt(NH3)(Br)(Cl)(py)] is [Mabcd] type square planar complexIt has two cis isomers and one trans isomer.∴ X =3 .B) [Pt(NH3)2Cl2] is [Ma2b2] type square planar complex.It is has a cis isomer and a trans isomer∴ Y =2 .