Q.

The number of water molecules present in a drop of water (volume 0.0018 mL) at room temperature is:

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a

6.023×1019

b

5.023×1023

c

1.084×1018

d

4.84×1017

answer is A.

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Detailed Solution

Weight of H2O = V x d = 0.0018 mL x 1 = 0.0018 g nH2O=0.001818=10-4mol=6.023 ×1023×10-4=6.023×1019
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