Q.
The number of water molecules present in a drop of water (volume 0.0018 mL) at room temperature is:
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a
6.023×1019
b
5.023×1023
c
1.084×1018
d
4.84×1017
answer is A.
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Detailed Solution
Weight of H2O = V x d = 0.0018 mL x 1 = 0.0018 g nH2O=0.001818=10-4mol=6.023 ×1023×10-4=6.023×1019
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