First slide

Relation between Delta H and Delta U

Question

At $27^{o} C$ for the combustion of two mole of benzene, $∆ H - ∆ E$ is equal to

Easy

A

-3.74 kJ
B

-7.48 kJ
C

+1.25 kJ
D

-1.25 kJ

Solution

$2 C_{6} H_{6} (l) + 15 O_{2} (g) \overset{}{\to} 12 {CO}_{2} (g) + 6 H_{2} O (l); ∆ n_{g} = 12 - 15 = - 3; ∆ H - ∆ E = ∆ nRT; = - 3 (8.314 \times 10^{- 3} {KJmol}^{- 1} K^{- 1}) (300 K); = - 7.48 kJ;$

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