. At 527oc, the reaction given below has Kc =4 NH3(g)⇌12 N2(g)+32H2(g) What is the K p ( for the reaction? N2(g)+3H2(g)⇌2NH3(g)

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16×(800R)2

800R4-2

14×800R2

None or these

answer is C.

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Detailed Solution

if kc=N21/2H23/2NH31=4then NH32 N2H23=(4)-2=116 kp=kc·(RT)Δng ; ∆ng=2-(1+3)=2-4=-2, T=527°c=800K Kp=116(800R)-2

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