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Q.

At 25oC the vapour pressure of benzene, C6H6 (78 g/mole), is 93.2 Torr and that of toluene, C7H8 (92 g/mol), is 28.2 torr. A solution of 1.0 mole of C6H6 and 1.0 mol of C7H8 is prepared. Calculate the mole fraction of C6H6 in the vapour above this solution (assume the solution is ideal).

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a

0.607

b

0.768

c

0.232

d

0.393

answer is B.

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Detailed Solution

YB=PBo×XBPYB=93.2×0.5PTYT=28.2×0.5PT∴YBYT=3.3 & YB+YT=1On solving yB=0.768
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