At 25oC vapour pressure of a volatile liquid A is 60 torr. To 4 mol of A, x moles of another volatile liquid B is added at 25oC . The vapour pressure of the resulting solution was found to be 72 torr and mole fraction of A in the vapour phase was 1/3. The value of x is

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answer is 6.

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Detailed Solution

PA0XAPB0XB=12............(1) PA0XA+PB0XB=72........(2) Solving (1) & (2) gives XAXB=23 Thus moles of ‘B’ added =6

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