% of _________=100 (0.16(XA-XB)+0.035(XA-XB)2)In the above equation XA and XB is electronegativity of A and B respectively.What will be in the blank as shown above.
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a
Covalent charecter
b
Ionic charecter
c
Ionic resonance energy
d
Electron affinity
answer is B.
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Detailed Solution
% of ionic charecter=100 (0.16(XA-XB)+0.035(XA-XB)2)
% of _________=100 (0.16(XA-XB)+0.035(XA-XB)2)In the above equation XA and XB is electronegativity of A and B respectively.What will be in the blank as shown above.