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a
LiAlH4
b
B2H6
c
NaBH4
d
Both 1 and 2
answer is B.
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Detailed Solution
LiAlH4 and B2H6 can reduce –COOH-to-CH2OH, LiAlH4 reduces –NO2 group to –NH2 group. B2H6 cannot reduce -NO2 group.∴O2N−CH2−COOH→B2H6O2N−CH2−CH2OHO2N−CH2−COOH→LiAlH4H2N−CH2−CH2OH