Observe the following reactions, A+C6H5SO2Cl ⟶-OH⟶KOH Clear solution →H+ Substance is soluble in acidic mediumB+C6H5SO2Cl⟶-OH Insoluble substance in H+/OH-C+C6H5SO2Cl⟶-OH Insoluble in base but soluble in H+⟶H+ Clear solution.A, B and C are respectively
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a
1o, 3o and 2o amines
b
1o, 2o and 3o amines
c
1o, aniline and 2o amine
d
1o amine, 2o amine and aniline
answer is B.
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Detailed Solution
1o amine forms N-alkyl benzene sulphonamide with C6H5SO2Cl which is soluble in alkali.2o amine forms N, N-dialkyl benzene sulphonamide, which is insoluble in alkali as well as acid.3o amines do not react with C6H5SO2Cl and hence are soluble in acid. Thus, A, B, and C here represent 1o, 2o and 3o amines respectively.