First slide

PH of strong acids and strong bases

Question

The [OH^–] of 0.005 M H₂SO₄ is

Easy

A

2 x 10^-10
B

5 x 10^-3
C

10^-2M
D

10^-12M

Solution

$\Rightarrow [H_{2} {SO}_{4}] = 5 \times 10^{- 3} M$ $\Rightarrow [{OH}^{+}] = 10^{- 2} M$
P^H = 2
$\Rightarrow [{OH}^{-}] = 10^{- 12} M$

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