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Q.

[OH-] in a solution prepared by mixing equal volumes of 0.3 M methylamine (CH3NH2 , Kb  = 3 .7 x 10-4) and 0.60 M CH3NH3+Cl-

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a

3.7×10−4M

b

7.4×10−4M

c

3.7×10−2M

d

1.85×10−4M

answer is D.

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Detailed Solution

CH3NH2+H2O⇌CH3NH3++OH− Kb=CH3NH3+OH−CH3NH2 3.7×10−4=0.60OH−0.3 ∴ OH−=1.85×10−4M
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[OH-] in a solution prepared by mixing equal volumes of 0.3 M methylamine (CH3NH2 , Kb  = 3 .7 x 10-4) and 0.60 M CH3NH3+Cl-