Q.

One gram of Na3AsO4 is boiled with excess of solid KI in presence of strong HCl. The iodine evolved is absorbed in KI solution and titrated against 0.2 N hyposolution. Assuming the reaction to beAsO43- + 2H+ + 2I- →  AsO33- + H2O + I2,calculate the volume of thiosulphate hypo consumed. [Atomic weight of As = 75]

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a

48.1 mL

b

38.4 mL

c

24.7 mL

d

30.3 mL

answer is A.

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Detailed Solution

As+5O4-3+2H++2I-→As+3O3-3+H2O+I2molar mass Na3AsO4= 23 x 3 + 75 + 16 x 4molar mass = 208eq. of AsO4-3 = 12082 = 1104equivalent of  Na3AsO4 = equivalent of I2= equivalent of Na2S2O31104 = .2 × V 1104 × .2 L = V = 48.1 mL
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