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Q.

One litre of a gas at STP weight 1.16 g, it can possible only for

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a

C2H2

b

CO

c

O2

d

CH4

answer is A.

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Detailed Solution

∵ 1 L of gas at S.T.P. weight 1.16 g∴ 22.4 L of gas at S.T.P. weight = 22.4 × 1.16 = 25.984 ≈ 26This molecular weight indicates that given compound is C2H2.

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