Q.
One litre of a gas at STP weight 1.16 g, it can possible only for
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a
C2H2
b
CO
c
O2
d
CH4
answer is A.
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Detailed Solution
∵ 1 L of gas at S.T.P. weight 1.16 g∴ 22.4 L of gas at S.T.P. weight = 22.4 × 1.16 = 25.984 ≈ 26This molecular weight indicates that given compound is C2H2.
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