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Q.

One litre of a gas at STP weight 1.16 g, it can possible only for

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a

C2H2

b

CO

c

O2

d

CH4

answer is A.

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Detailed Solution

∵   1 L of gas at S.T.P. weight 1.16 g∴   22.4  L of gas at  S.T.P. weight  =  22.4  ×  1.16                                                                                                                    =  25.984  ≈  26This molecular weight indicates that given compound is C2H2.
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