To a one litre solution containing 8 grams of sodium hydroxide, 14.7 grams of sulphuric acid is added. pH of the solution at 298 K is
Number of gram equivalents of base = 8/40 = 0.2
Number of gram equivalents of acid = 14.7/49 = 0.3
Nature of resultant solution is acidic
Number of gram equivalents of acid left = (0.3 - 0.2)