To a one litre solution containing 4 grams of sodium hydroxide, 9.8 grams of sulphuric acid is added pH of the solution at 298 K is
Number of gram equivalents of base = 4/40 = 0.1
Number of gram equivalents of acid = 9.8/49 = 0.2
Nature of resultant solution is acidic
Number of gram equivalents of acid left = (0.2 - 0.1)
Number of gram equivalents of acid left = 0.1