Q.

One mole of calcium carbonate on thermal decomposition gives ‘X’ grams of residue. ‘X’ on heating with coke gets completely converted to ‘Y’ grams of solid. ‘Y’ grams of this solid on hydrolysis gives 19.5 grams of a gaseous product ‘Z’ . Percentage yeild of ‘Z’ obtained is

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answer is 4.

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Detailed Solution

CaCO3s1  mole→CaOs1  mole+CO2gCaOs1  mole56 g+3Cs→CaC2s1  mole64 g+COgCaC264 gs+2H2O→C2H226 gg+CaOH2If  the  yield  of  C2H2  is  100%  then  weight   ofC2H2  formed  must  be  26 g but only  19.5g  of  C2H2  is formced∴%yiel  of  product=19.526×100=75%
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