One mole of a compound AB reacts with one mole of a compound CD according to the equation $$AB(g)+CD(g)$$⇌$$AD(g)+CB(g)$$ . When equilibrium had been established it was found that $$3/4$$ mole of reactants AB and CD had been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is

Question

One mole of a compound AB reacts with one mole of  a compound CD according to the equation $$AB(g)+CD(g)$$⇌$$AD(g)+CB(g)$$      . When  equilibrium had been established it was found that $$3/4$$ mole of reactants AB  and CD had been converted to AD and CB. There is no change in volume. The  equilibrium constant for the reaction is

Infinity Learn · Accepted Answer

$$AB(g)+CD(g)$$⇌$$AD(g)+CB(g)$$           $$1$$             $$1$$                   $$0$$              $$0$$           $$34$$           $$34$$                  $$34$$             $$34$$  $$_$$        $$14$$           $$14$$                  $$34$$              $$34$$            ∴ $$Kc=(34)(34)(14)(14)=9$$

Detailed Solution

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