Q.
One mole of a compound AB reacts with one mole of a compound CD according to the equation AB(g)+CD(g)⇌AD(g)+CB(g) . When equilibrium had been established it was found that 3/4 mole of reactants AB and CD had been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is
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a
916
b
19
c
169
d
9
answer is D.
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Detailed Solution
AB(g)+CD(g)⇌AD(g)+CB(g) 1 1 0 0 34 34 34 34 _ 14 14 34 34 ∴ Kc=(34)(34)(14)(14)=9
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