Q.

One mole of a compound AB reacts with one mole of a compound CD according to the equation AB(g)+CD(g)⇌AD(g)+CB(g)  . When equilibrium had been established it was found that 3/4 mole of reactants AB and CD had been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is

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a

916

b

19

c

169

d

9

answer is D.

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Detailed Solution

AB(g)+CD(g)⇌AD(g)+CB(g)     1             1                   0              0       34           34                  34             34  _    14           14                  34              34        ∴ Kc=(34)(34)(14)(14)=9
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