One mole of Ferrous oxalate can reduce ‘X’ moles of KMnO4 in acidic medium
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a
35
b
63
c
53
d
36
answer is A.
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Detailed Solution
Total increase in ox.state/mole of ferrous oxalate = 3Total decrease in ox.state/mole of pot.permanganate = 5∴5 moles of FeC2O4 can reduce 3 moles of KMnO4/H+1 mole of FeC2O4 can reduce ‘X’ moles of KMnO4/H+∴X=35