One mole of A(g) is heated to 2000C in a 1 lit closed flask, till the following equilibrium is reached A(g) ⇌ B(g). The rate of forward reaction at equilibrium is 0.02 mole.lit-1.min-1. What is the rate (in mole.lit-1.min-1) of the backward reaction at equilibrium ?
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a
0.04
b
0.01
c
0.02
d
1
answer is C.
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Detailed Solution
At equilibrium rate of forward reaction = rate of backward reaction. rf = rb =0.02 mole/lit/min