One mole of an ideal gas is allowed to expand reversibly and adiabatically at a temperature of 27°C. If the work done during the process is 3 kJ, the final temperature will be equal to (Cv = 20 J K-1)
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a
150 K
b
100 K
c
26.85 K
d
295 K
answer is A.
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Detailed Solution
During adiabatic expansion, the work done = CvT2−T1 or −3000=20T2−300 or T2=150K