One mole of an ideal gas is heated at constant pressure from 0°C to 100°C..Calculate work done

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answer is 198.7 CAL.

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Detailed Solution

Work involved in heating of gasWa=−P⋅ΔV=−PV2−V1=−PnRT2P−nRTP=−nRT2−T1=−1×1.987(373−273)=−198.7cal

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