One mole of an ideal gas is put through a series of changes as shown in the figure in which 1, 2, 3 mark the three stages of the system. Find the Pressure at the three stages.

At stage (1)V=22.4L=22.4×10−3m3T = 300 K, n = 1 mol.p=nRTV=1mol×8.314Pam3mol−1K−1×300K22.4×10−3m3- 1.1 13 x l05 Pa = 1.113 barAt stage (2) temperature is doubled but volume is constant. Thus, P∝T,=2.226barAt stage (3), T is 300 K and V is 11.2 L and as in stage (1).p=nRTV=2.226bar