One mole of pure ethyl alcohol was treated with one mole of pure acetic acid at 25oC. One-third of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be :

C2H5OH(l)+CH3COOH(l)⇌CH3COOC2H5(l)+H2O(l)t = 0;  1 mole              1 mole                          0                     0teq. ;    1-x                    1-x                                x                     xx=13 kc=CH3COOC2H5H2OC2H5OHCH3COOH=1/3×1/32/3×2/3=14