One mole of SO3 was placed in a litre reaction flask at a given temperature when the reaction equilibrium was established in the reaction.2SO3⇌2SO2+O2the vessel was found to contain 0.6 mol of SO2. The value of the equilibrium constant is

2SO3       ⇌            2SO2      +        O2 Initial                     1                              0                      0 At equilibrium    1 - 2x                     2x                      x ∴2x=0.6,∴x=0.3SO3=1−2x=1−0.6=0.4SO2=2x=0.6O2=x=0.3K=x×(2x)2(1−2x)2=0.3×0.6×0.60.4×0.4=0.675