One mole of $$SO3$$ was placed in a litre reaction flask at a given temperature when the reaction equilibrium was established in the $$reaction.2SO3$$⇌$$2SO2+O2the$$ vessel was found to contain $$0.6$$ mol of $$SO2$$. The value of the equilibrium constant is

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$$2SO3$$       ⇌            $$2SO2$$      $$+$$        $$O2$$ Initial                     $$1$$                              $$0$$                      $$0$$ At equilibrium    $$1$$ $$-$$ $$2x$$                     $$2x$$                      x ∴$$2x=0.6$$,∴$$x=0.3SO3=1$$−$$2x=1$$−$$0.6=0.4SO2=2x=0.6O2=x=0.3K=x$$×$$(2x)2(1$$−$$2x)2=0.3$$×$$0.6$$×$$0.60.4$$×$$0.4=0.675$$

Chemical Equilibrium

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One mole of SO₃ was placed in a litre reaction flask at a given temperature when the reaction equilibrium was established in the reaction.
$2 {SO}_{3} ⇌ 2 {SO}_{2} + O_{2}$
the vessel was found to contain 0.6 mol of SO₂. The value of the equilibrium constant is

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Chemical Equilibrium

Unlock the full solution & master the concept.

One mole of SO3 was placed in a litre reaction flask at a given temperature when the reaction equilibrium was established in the reaction.2SO3⇌2SO2+O2the vessel was found to contain 0.6 mol of SO2. The value of the equilibrium constant is

2SO3 ⇌ 2SO2 + O2 Initial 1 0 0 At equilibrium 1 - 2x 2x x ∴2x=0.6,∴x=0.3SO3=1−2x=1−0.6=0.4SO2=2x=0.6O2=x=0.3K=x×(2x)2(1−2x)2=0.3×0.6×0.60.4×0.4=0.675

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One mole of SO₃ was placed in a litre reaction flask at a given temperature when the reaction equilibrium was established in the reaction.
$2 {SO}_{3} ⇌ 2 {SO}_{2} + O_{2}$
the vessel was found to contain 0.6 mol of SO₂. The value of the equilibrium constant is