One mole of Sodium bicarbonate on strong heating suffers a loss in weight of

Weight lost =  Weight of gas liberated out;Temperature required to decompose NaHCO3 is so high that water also is liberated out as vapour ;2NaHCO3s →∆ Na2CO3s+CO2g+H2Og;   2moles                                         44g          18g........62g(total)   1mole                                           22g            9g........31g(total)