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Q.

One mole of a solute A  is dissolved in a given volume of a solvent. The association of the solute take place as follows  n A ⇌  An. If a is the degree of association of A, the Van’t Hoff factor i  is expressed as

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a

i=1−α

b

i=1+αn

c

i=1−α+αn

d

i=1

answer is C.

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Detailed Solution

nA⇌ Anat Initial mole  =1 ,     ni=1At equilibrium state. 1−α          αn,  ⇒ neq=1−α+αn ( \ i = Van’t Hoff factor)  ∴i=neqni   =1−α+αn1             ( \ i = Van’t Hoff factor)  i=1−α+αn
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