Q.

An open bulb containing air at 290C was cooled to a certain temperature at which the number of moles of the gaseous molecules increased by 50%. The final temperature is

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a

39.6 K

b

233.6 K

c

201.3 K

d

240 K

answer is C.

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Detailed Solution

n1T1=n2T2 n1=(xm)           T1=302K n2=xM+x2M=3x2M       T2=? xM×0.302=3x2M×T2⇒6003=201.3K
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An open bulb containing air at 290C was cooled to a certain temperature at which the number of moles of the gaseous molecules increased by 50%. The final temperature is