Q.
An open bulb containing air at 290C was cooled to a certain temperature at which the number of moles of the gaseous molecules increased by 50%. The final temperature is
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a
39.6 K
b
233.6 K
c
201.3 K
d
240 K
answer is C.
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Detailed Solution
n1T1=n2T2 n1=(xm) T1=302K n2=xM+x2M=3x2M T2=? xM×0.302=3x2M×T2⇒6003=201.3K
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