Q.
The optical rotation of an optically active compound is +20° the length of tube 10 cm and the density of solution is 0.4 g L-1. The specific rotation of the compound is
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a
+50°
b
+500°
c
+5°
d
+0.5°
answer is A.
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Detailed Solution
10 cm =1dm (specific rotation [α]Dl=θl×c)[α]=+2001×0.4=+500Where l = length of tube in decimeterc=concentration of solution in g/mlD=Wave lengthθ = optical rotation
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