The orbit angular momentum and orbital angular momentum for electron are 3h2π and 32hπ Then the number of radial nodes and angular nodes for that atomic orbital will be
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a
1, 1
b
0, 1
c
0, 2
d
2, 0
answer is C.
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Detailed Solution
Orbit angular momentum=nh2π nh2π=3h2π therefore n = 3,orbital angular momentum =ℓ(ℓ+1)h2πℓ(ℓ+1)h2π=32hπ ℓ(ℓ+1)2=32ℓ(ℓ+1)=6 l = 2Number of radial nodes = n - l -1 = 3 - 2 - 1 = 0Number of angular nodes = l = 2