The orbit and orbital angular momentum of an electron are 3h2π and 32hπ respectively.The number of radial and angular nodes for the orbital in which the electron is present are respectively.
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a
0, 2
b
2, 0
c
1, 3
d
2, 2
answer is A.
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Detailed Solution
Orbit angular momentum =nh2π=3h2π Thus n=3,hence orbit is 3 Orbital angular momentum=ll+1 h2π=32.hπ we can conclude that l=2, hence the orbital is 3d Number of radial nodes=n-l-1=3-2-1=0 Number of angular nl=l=2