In order to determine the volume of blood in an animal, a 1.0 mL sample of solution of 103 dpm of ,H3 is injected into the animal blood stream. After sufficient time for circulatory equilibrium to be established, 2 mL of blood is found to haveactivity to 10 dpm. The volume of blood in animal is:
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a
199 mL
b
198 mL
c
200 mL
d
20 mL
answer is A.
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Detailed Solution
No change in activity of sample during establishment of circulatory equilibrium.Let volume of blood is V mL, so total vol. = (V + l) mL after injection of sample.2mL sample has activity of 10 dpm, so (V+ l) mL sample has activity of 102×(V+1) Since rate is constant so102×(V+1)=1000;V=199mL