Q.

An organic compound on analysis gave C = 48 g, H : 8 g and N : 56 g. Volume of 1.0 g of the compound was found to be 200 ml at NTP. Molecular formula of the compound is

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a

C4H8N4

b

C2H4N2

c

C12H24N12

d

C16H32N16

answer is A.

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Detailed Solution

Empirical formula = CH2NEmpirical formula mass = 28Now, 200 ml of compound = 1 g22400 ml  of compound  1200 × 22400 = 112g ; n = Mol. of massEmp. formula mass  = 11228=4 Therefore, Molecular formula = CH2N4 = C4H8N4.
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An organic compound on analysis gave C = 48 g, H : 8 g and N : 56 g. Volume of 1.0 g of the compound was found to be 200 ml at NTP. Molecular formula of the compound is