An organic compound on analysis was found to contain 10.06% carbon, 0.84% hydrogen and 89.10% chlorine. What will be the empirical formula of the substance?
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a
CH2Cl2
b
CHCl3
c
CCl4
d
CH3Cl
answer is B.
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Detailed Solution
Thus, the empirical formula of the substance is CHCl3.
An organic compound on analysis was found to contain 10.06% carbon, 0.84% hydrogen and 89.10% chlorine. What will be the empirical formula of the substance?