An organic compound containing C, H and O has 49.3% A carbon , 6.84% hydrogen and its vapour density is 73. Molecular formula of the compound is

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C3H5O2

C4H10O2

C6H10O4

C3H10O2

answer is C.

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Detailed Solution

The empirical formula is C3H5O2. Empirical formula weight = 3 x 12+ 5 x 1+ 2x 16 = 36+5+32=73Molecular weight of the compound = 2x VD = 2x 73 = 146n= mol. wt. empirical formula wt. =14673=2Molecular formula = Empirical formula x 2 = (C3H5O2) ×2=C6H10O4

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