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Qualitative analysis

Question

An organic compound containing phosphorous is heated with ${Na}_{2} O_{2}$ and then boiled with conc. ${HNO}_{3}$ . To this solution a reagent ‘X’ is added. The oxidation state of phosphorous in the canary yellow coloured compound ‘Y’ formed is

Easy

A

+1
B

+3
C

+4
D

+5

Solution

$Organic compound \to_{b) Conc . {HNO}_{3}}^{a) {Na}_{2} O_{2}} H_{3} {PO}_{4} H_{3} {PO}_{4} + 12 {({NH}_{4})}_{2} {MoO}_{4} + 21 {HNO}_{3} \overset{}{\to} {({NH}_{4})}_{3} {PO}_{4} . 12 {MoO}_{3} + 21 {NH}_{4} {NO}_{3} + 12 H_{2} O Canary yellow coloured precipitate is ammonium phospho molybdate, {({NH}_{4})}_{3} {PO}_{4} . 12 {MoO}_{3} {[\overset{- 3}{N} {\overset{+ 1}{H}}_{4}]}_{3} \overset{+ 5}{P} {\overset{- 2}{O}}_{4} . 12 \overset{+ 6}{M} o \overset{- 2}{O_{3}}$

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