An organic compound contains 40% by weight of carbon and 6.66% by weight of Hydrogen. Empirical formula of the compound is

	$\mathrm{C}$	$\mathrm{H}$	$\mathrm{O}$
$\mathrm{Percentage} \mathrm{of} \mathrm{weight}$	$40$	$6.66$	$(100 – 46.66)=53.34$
$\mathrm{Number} \mathrm{of} \mathrm{gram} \mathrm{atoms}$	$\frac{40}{12}=3.33$	$\frac{6.66}{1}=6.66$	$\frac{53.34}{16}=3.33$
$\mathrm{Number} \mathrm{of} \mathrm{gram} \mathrm{atoms}$	$\frac{3.33}{3.33}=1$	$\frac{6.66}{3.33}=2$	$\frac{3.33}{3.33}=1$

$\mathrm{Empirical} \mathrm{Formula}$ = ${\mathrm{CH}}_2\mathrm{O}$