An organic compound has an empirical formula (CH2O). Its vapour density is 45. The molecular formula of the compound is
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a
CH2O
b
C2H5O
c
C2H2O
d
C3H6O3
answer is D.
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Detailed Solution
Mol. wt. =2× vapour density =2×45=90Empirical formula weight = 12 + 2 +16 = 30n= mol. wt. empirical formula wt. =9030=3∴ Molecular formula of the compound =CH2O3=C3H6O3