Q.

An organic compound has an empirical formula (CH2O). Its vapour density is 45. The molecular formula of the compound is

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a

CH2O

b

C2H5O

c

C2H2O

d

C3H6O3

answer is D.

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Detailed Solution

Mol. wt. =2× vapour density =2×45=90Empirical formula weight = 12 + 2 +16 = 30n= mol. wt.  empirical formula wt. =9030=3∴ Molecular formula of the compound =CH2O3=C3H6O3
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