In an organic compound of molar mass 108 gm mol 1 C, H and N atoms are present in 9 : 1 : 3.5 by weight. Molecular formula can be :

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C6H8N2

C7H10N

C5H6N3

C4H18N3

answer is A.

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Detailed Solution

Mole CHN912113.51434:1:143:4:1 n=10854=2⇒C3H4N⇒M.F=C3H4NnMF=C3H4N2=C6H8N2

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