Q.

The osmotic pressure of blood is 7.65 atm. at 310 K. An aqueous solution of glucose which is isotonic with blood has the percentage (wt./volume)

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5.41

3.54

4.53

53.4

answer is A.

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Detailed Solution

Since glucose and blood are isotonic, the osmotic pressures are the same. Therefore, πglucose=πbloodπ =CST π =nvST πV =nST 7.65×V=w180×0.0821×310 [w = amount of glucose present in V litres solution] 7.65×180=wV×0.0821×310 wV=7.65×1800.0821×310=54.1 g L−1 or 5.41%

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