First slide

13th group or boron group

Question

The oxidation of NaBH₄ (Sodium Boro Hydride) with Iodine gives

Moderate

A

$B_{2} H_{6}$
B

$H_{2} O$
C

B
D

NaH

Solution

$2 {NaBH}_{4} + I_{2} \to B_{2} H_{6} + 2 NaI + H_{2}$

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