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Q.

The oxidation number coordination number and magnetic moment for the complex are CrC2O42NH32− respectively.

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a

O.N. =+3, C.N. =6, M.M. =15 B.M.

b

O.N. =+1, C. N.=6,M.M.=15 B.M.

c

O.N. =+3, C. N.=6, M.M. =3 B.M.

d

O.N. =+3, C.N. =6, M.M. =24 B.M.

answer is A.

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Detailed Solution

CrC2O42NH32−1  O.N. (Cr)=+3,C⋅N.=6,M⋅M=15BM  No. of unpaired electron =3.
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