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The oxidation number of Cr is +6 in

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a

FeCr2O4

b

KCrO3Cl

c

CrO5

d

Cr(OH)4⊝

answer is B.

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Detailed Solution

(1) Fe+2Cr2O42−: Oxidation state of Cr = +3(2) K⊕CrO3Cl⊖: Oxidation state of Cr = +6(3) Oxidation state of Cr = +6. (Two peroxo linkage)(4) Cr(OH)4⊖:Oxidation state of Cr = +3

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