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Q.

Oxidation number of P in PO43−, S in SO42− and Cr in Cr2O72− are respectively.

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a

+3, +6 and +5

b

-3, + 6 and + 6

c

+5, +3 and +6

d

+5, +6 and +6

answer is D.

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Detailed Solution

PO4-3 x+4(-2)=-3 x-8=-3 x=+5 SO4-2 x+4(-2)=-2 x-8=-2 x=+6 Cr2O7-2 2x+7(-2)=-2 2x-14=-2 2x=+12 x=+12/2 x=+6
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