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Q.

The oxidation number of phosphorus in BaH2PO22 is :

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a

+3

b

+2

c

+1

d

-1

answer is C.

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Detailed Solution

Ba(H2PO2)2Ba+2  ; (H2PO2)- O.S of  P =                   [2(+1)+ X+2(-2)] =-1 X=1 O.S of  P =+1
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