First slide

IUPAC Nomenclature

Question

The oxidation number of Pt in ${[Pt (C_{2} H_{4}) {Cl}_{3}]}^{-}$ is

Easy

A

+ 1
B

+ 2
C

+ 3
D

+ 4

Solution

$\begin{array}{l} {[\underset{x}{Pt} (\underset{0}{C_{2}} H_{4}) \underset{- 1}{{Cl}_{3}}]}^{-} \\ x + 0 + 3 (- 1) = - 1, x - 3 = - 1, x = + 2 \end{array}$

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