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Oxidation number of in is :
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a
+6
b
+3
c
+2
d
-2
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Correct option is A
Oxidation number (O.N.) of S in SO42−found as :O.N. of S+4 (O.N. of O ) =−2O.N. of S+4(−2)=−2O.N. of S−8=−2O.N. of S=−2+8=+6.Talk to our academic expert!
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