Oxidation potential of Hydrogen electrode in contact with 0.05 M ${\mathrm{H}}_2{\mathrm{SO}}_4$ solution is 

$$\begin{gathered} {\mathrm{E}}_{\mathrm{RP}} = –0.0591{\mathrm{p}}^{\mathrm{H}}; \\ \left[{\mathrm{H}}^{+}\right]=0.05\times 2=0.1\mathrm{N} ; \\ {\mathrm{p}}^{\mathrm{H}} = 1 ; \\ {\mathrm{E}}_{\mathrm{RP}} = –0.0591\left(1\right) \mathrm{V} ; \\ {\mathrm{E}}_{\mathrm{RP}} = –0.0591\mathrm{V}; \\ {\mathrm{E}}_{\mathrm{OP}} = +0.0591\mathrm{V} ; \end{gathered}$$